Jharkhand Combined Entrance Competitive Examination Board (JCECEB) is going to invite online applications in April, 2018 for Jharkhand Polytechnic Entrance Competitive Examination 2018 popularly known as Jharkhand PECE for admission to diploma programs offered by the polytechnics in state for academic session 2018-2019. Read about Jharkhand Polytechnic Admission 2018 eligibility criteria, application procedure, important dates, exam dates exam pattern and other details on Jharkhand PECE 2018.
Jharkhand PECE 2018 eligibility criteria
Candidates residing in Jharkhand (have domicile) permanently can apply for Jharkhand Polytechnic Entrance Competitive Examination 2018.
Age limit– Candidate must have attained the age of 17 years on or before 1st July, 2018 only for mining engineering diploma courses for rest of the courses there is no minimum or maximum age applied.
Educational Qualification– Candidate must have passed 10th/Madhyamik or any other equivalent examination with 35% marks in aggregate can apply for Jharkhand Polytechnic Entrance Test 2018. Candidates waiting for their result or appearing for examination can also apply for the same.
Jharkhand PECE 2018 application form
Eligible candidates can apply at http://jceceb.jharkhand.gov.in/ or visit http://jceceb.nic.in click “Online application for PECE-2018” follow the instructions give to apply on or before 15 April, 2018.
Jharkhand PECE 2018 Application fee of Rs. 600 (Rs. 325 for SC/ST/Female candidates) can be submitted online through Credit card/Debit card/Net banking.
Jharkhand Polytechnic admission 2018 Important dates
- Last date to apply for Jharkhand Polytechnic Entrance Test 2018- 15 April, 2018
- Jharkhand PECE 2018 entrance test date- 30 April, 2018, Sunday (10 am to 12:30 pm)
Jharkhand Polytechnic Admission 2018 exam pattern
Test paper will consist of 150 Multiple Choice Questions 50 each from Physics, Chemistry and Math of 150 marks. Total duration of the exam will be 2 hours 30 minutes. For every correct answer one marks will be awarded and for every wrong answer 0.25 marks will be deducted.